c programming code for simple calculator
Here is the code for writing c programming code for menu driven calculator doing addition ,subtraction,division and multiplication using switch case.
#include<stdio.h>
int main()
{
int a,b,choice;
printf("enter any two numbers\n");
scanf("%d%d",&a,&b)
do
{
printf("\n1.Addition\n2.Subtraction\n3.Multiplication\n4.Division\n5.Exit\n");
printf("enter any choice\n");
scanf("%d",&choice);
switch(choice)
{
case 1:
if(choice==1)
printf("addition of given number is %d",a+b);
break;
case 2:
if(choice ==2)
printf("subtraction of given numbers is %d",a-b);
break;
case 3:
if(choice ==3)
printf("multiplication of given numbers is %d",a*b);
break;
case 4:
if(choice==4)
printf("division of given numbers is %d",a/b);
break;
default:
printf("invalid choice \n");
}
}
while(choice!=5);
}
Result of the above program
int main()
{
int a,b,choice;
printf("enter any two numbers\n");
scanf("%d%d",&a,&b)
do
{
printf("\n1.Addition\n2.Subtraction\n3.Multiplication\n4.Division\n5.Exit\n");
printf("enter any choice\n");
scanf("%d",&choice);
switch(choice)
{
case 1:
if(choice==1)
printf("addition of given number is %d",a+b);
break;
case 2:
if(choice ==2)
printf("subtraction of given numbers is %d",a-b);
break;
case 3:
if(choice ==3)
printf("multiplication of given numbers is %d",a*b);
break;
case 4:
if(choice==4)
printf("division of given numbers is %d",a/b);
break;
default:
printf("invalid choice \n");
}
}
while(choice!=5);
}
hello world!
ReplyDeleteVery good way of writing.
ReplyDeleteVERY HELPFUL SIR I WISH I COULD LEARN SOMETHING FROM U
ReplyDelete